A uniform electric field 400 N/C acts along positive y-axis. P is a point having co-ordinates (0.6 m, -0.2 m) and R another point, with co-ordinates (-0.4 m, 0.6 m). If electric potential at P is 200 V, potential at R will be :

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100 V

-150 V

80 V

-120 V

answer is D.

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Detailed Solution

∆V=VR-VP=-E→.∆r→=-E→rR→-rP→ ⇒VR-200=-(-400 j^).(-i^+0.8 j^) ⇒VR-200=-320 ⇒VR=-120 volt

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