In an uniform field the magnetic needle completes 10 oscillations in 92 seconds. When a small magnet is placed in the magnetic meridian 10 cm due north of needle with north pole towards south completes 15 oscillations in 69 seconds. The magnetic moment of magnet (BH = 0.3 G) is
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a
4.5 Am2
b
0.45 Am2
c
0.75 Am2
d
0.225 Am2
answer is C.
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Detailed Solution
f1f=B1B ; 9210 x 1569=B10.3 ; B1=1.2 GB1-BH=1.2 ; B1=1.5 G =1.5×10-4 Tμ04π2Md3=B1 ; M=0.75 Am2