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Q.

A uniform force of  (3i^+j^)N acts on a particle of mass 2 kg. Hence, the particle is displaced from (2i+k)m to position (4i^+3j^-k^)m The work done by the force on the particle is [NEET 2013)

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a

9 J

b

6 J

c

13 J

d

15 J

answer is A.

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Detailed Solution

Given, force, F=(3i^+j^)Nr1=(2i^+k^)m and r2=(4i^+3j^-k^)m∴     s=r2-r1=(4i^+3j^-k^)-(2i^+k^)=(2i^+3j^-2k^)m∴   W=F·s=(3i^+j^)·(2i^+3j^-2k^)=3×2+1×3+0=6+3=9 J
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