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A uniform force of  (3i^+j^)N acts on a particle of mass 2 kg. Hence, the particle is displaced from (2i+k)m to position (4i^+3j^-k^)m The work done by the force on the particle is [NEET 2013)

a
9 J
b
6 J
c
13 J
d
15 J

detailed solution

Correct option is A

Given, force, F=(3i^+j^)Nr1=(2i^+k^)m and r2=(4i^+3j^-k^)m∴     s=r2-r1=(4i^+3j^-k^)-(2i^+k^)=(2i^+3j^-2k^)m∴   W=F·s=(3i^+j^)·(2i^+3j^-2k^)=3×2+1×3+0=6+3=9 J

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