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Q.

A uniform force of (3i^+j^) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i^+k^) meter to position (4i^+3j^-k^) meter. The work done by the force on the particle is

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a

15 J

b

9 J

c

6J

d

13J

answer is B.

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Detailed Solution

W=F→⋅S→=(3i^+j^)⋅[(4−2)i^+(3−0)j^+(−1−1)k^]=(3i^+j^)⋅(2i^+3j^−2k^)=3(2)+1(3)+0(−2)=9J
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