First slide

Work done by Diff type of forces

Question

A uniform force of $(3 \hat{i} + \hat{j})$ newton acts on a particle of mass 2 kg. Hence the particle is displaced from position $(2 \hat{i} + \hat{k})$ metre to position $(4 \hat{i} + 3 \hat{j} - \hat{k})$ metre. The work done by the force on the particle is

Very Easy

Solution

$Applied force \vec{F} = 3 \hat{i} + \hat{j}$
Displacement $\vec{S} = \vec{r_{2}} - \vec{r_{1}} = 2 \hat{i} + 3 \hat{j} - 2 \hat{k}$
Hence work done W = $\vec{F} . \vec{S} = 6 + 3 + 0 = 9 J$

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