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Q.

A uniform force of (3i^+j^)newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i^+k^) metre to position (4i^+3j^-k^) metre. The work done by the force on the particle is

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Detailed Solution

Applied force F→ = 3i^+j^Displacement S → = r2→-r1→ = 2i^+3j^-2k^Hence work done W = F→.S→ = 6+3+0 = 9 J
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