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Q.

A uniform magnetic field B exists in the region between x=0 and x=3R2 (region 2 in the figure) pointing normally into the plane of the paper. A particle with charge +Q and momentum p directed along x-axis enters region 2 from region 1 at point P1y=−R. Which of the following option(s) is/are correct?

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a

When the particle re-enters region 1 through the longest possible path in region 2, the magnitude of the change in its linear momentum between point P1 and the farthest point from y-axis is p2

b

For B=813pQR, the particle will enter region 3 through the point  P2 on x-axis

c

For  B>23pQR, the particle will re-enter region 1

d

For a fixed B, particle of same charge Q and same velocity ν, the distance between the point  P1 and the point of re-entry into region 1 is inversely proportional to the mass of the particle

answer is B.

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Detailed Solution

For particle to re - enter region 1, radius of circular motion should be less than 3R2r<3R2⇒mvqB<3R2⇒B>2mv3QR⇒B>2p3QR∴Option (3) is correct Now, for complete semi circular path,  Initial Momentum at P1 =pi^ Final Momentum at P2=pj^∴ Change in momentum from P1 & P2=pj^−pi^⇒ Magnitude of Change in momentum =p2+p2=2p ∴Option (1) is wrong Distance between the point P1 and the point of re-entry into region 1=d=2r=2pqB=2mvqB​⇒d∝m∴Option 4 is wrongr1−cosθ=R−−−−1​rsinθ=3R2−−−−−−2​2 ÷1 we get​rsinθr1−cosθ=3R2R​⇒2sinθ2cosθ22sin2θ2=32​⇒tanθ2=23−−−−3​tanθ=2tanθ21-tan2θ2∵tan2θ=2tanθ1-tan2θ tanθ=2231-232=125rsinθ=3R2​⇒r1213=3R2​⇒r=13R8⇒13R8=pQB⇒B=8p13QR∴option 2 is correct​
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