First slide

Force on a charged particle moving in a magnetic field

Question

A uniform magnetic field exists in region which forms an equilateral triangle of side a.· The magnetic field is perpendicular to the plane of the triangle. A charge q enters into this magnetic field perpendicular to a side with speed v. The charge enters from mid-point and leaves the field from mid-point of other side. Magnetic induction in the triangle is

Moderate

A

$\frac{m v}{q a}$
B

$\frac{2 m v}{q a}$
C

$\frac{m v}{2 q a}$
D

$\frac{m v}{4 q a}$

Solution

The charged particle moves in a circle of radius a/2.
$qvB = \frac{{mv}^{2}}{a / 2} or B = \frac{2 mv}{qa}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App