First slide

Force on a charged particle moving in a magnetic field

Question

A uniform magnetic field is at right angle to the direction of motion of protons. As a result, the protons describe a circular path of radius 2 .5 cm. If the speed of the protons is doubled, then the radius of the circular path will be

Easy

A

0.5 cm
B

2.5 cm
C

5.0 cm
D

7.5 cm

Solution

$\frac{{mv}^{2}}{r} = evB or r = (mv / eB)$
When v is doubled, r is also doubled, i.e., 5.0 cm.

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