A uniform magnetic needle is suspended from its center by a thread. Its upper end is now loaded with a mass of $$50$$ mg when the needle becomes horizontal. If the strength of each pole is $$98.1$$ $$ab-amp$$.cm & g is $$981$$ $$cm/s2$$, then the vertical component of the earth’s magnetic field is

Question

A uniform magnetic needle is suspended from its center by a thread. Its upper end is now loaded with a mass of $$50$$ mg when the needle becomes horizontal. If the strength of each pole is $$98.1$$ $$ab-amp$$.cm &  g is  $$981$$ $$cm/s2$$, then the vertical component of the earth’s magnetic field is

Infinity Learn · Accepted Answer

Taking moments about ‘O’ $$Mgl=mBvl+mBvl$$ ⇒$$Mg=2mBv$$→(1)Given$$,  $$M=50$$×$$10$$−$$3g$$ $$g=981$$ $$cm/s2$$ $$m=98.1$$ ab−amp.cm Then from equation $$(1) $$50$$×$$10$$−$$3$$×$$981=2$$×$$98.1$$×Bv $$Bv=0.25$$ gauss.

A uniform magnetic needle is suspended from its center by a thread. Its upper end is now loaded with a mass of 50 mg when the needle becomes horizontal. If the strength of each pole is 98.1 ab-amp.cm & g is ${981 cm/s}^{2}$ , then the vertical component of the earth’s magnetic field is

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A uniform magnetic needle is suspended from its center by a thread. Its upper end is now loaded with a mass of 50 mg when the needle becomes horizontal. If the strength of each pole is 98.1 ab-amp.cm & g is 981 cm/s2, then the vertical component of the earth’s magnetic field is

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A uniform magnetic needle is suspended from its center by a thread. Its upper end is now loaded with a mass of 50 mg when the needle becomes horizontal. If the strength of each pole is 98.1 ab-amp.cm & g is ${981 cm/s}^{2}$ , then the vertical component of the earth’s magnetic field is