First slide

Concept of potential energy

Question

A uniform meter scale of mass 2kg is suspended from one end. If it is displaced through an angle $60^{\circ}$ from the vertical, the increase in potential energy is

Moderate

A

9.8J
B

4.9J
C

19.6J
D

$9.8 (1 - \frac{\sqrt{3}}{2})$

Solution

$\begin{array}{l} U = m g \frac{l}{2} (1 - \cos θ) \\ U = 2 \times 9.8 \times \frac{1}{2} (1 - \cos 60) = 9.8 \times \frac{1}{2} = 4.9 J \end{array}$

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