A uniform rectangular plate is hanging vertically downward from a hinge that passes along its left edge. By blowing air at 12m/s over the top of the plate only, it is possible to keep the plate in a horizontal position, as illustrated in part (a) of the drawing. To what value of speed (in m/s) should the air be blown so that the plate is kept at 30∘angle with respect to the vertical, as in part (b) of the drawing? (assume the velocity beneath the plate is almost zero)
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a
2
b
62
c
125
d
122
answer is B.
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Detailed Solution
Case (I)Due to moving air at the top of the plate, pressure at the top is less than that at the bottom (due to Bernoulli’s theorem)Δp=12ρv2F=Δp.A(Where A is area of the plate; F acts at the midpoint of the plate and directed upwards)Mg acts as the midpoint of the plate and directed downwards.∴ For equilibrium, balance moments about the hinge. 12ρv2.A.L2=Mg.L2......1 Case (II)F'=12ρv'2A∴ For equilibrium, balance moments about the hinge.12ρv'2.A.L2=Mg.L2sin30∘.......2Dividing 21, we get⇒v'=v2=122=62 ms-1Therefore, the correct answer is (B)