Questions
A uniform ring of mass m and radius R is released from top of an inclined plane. The plane makes an angle θ with horizontal. The coefficient of friction between the ring and the plane is µ. Initially, the point of contact of ring and plane is P. Angular momentum of the ring about point P as a funtion of time t is
detailed solution
Correct option is B
Force of friction passes through point P, Hence, its torque about P will be zero. Only (mgsinθ) will have torque about P. Thus τ.t = ΔL or (mgRsinθ)t = LTalk to our academic expert!
Similar Questions
A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination 300. The centre of mass of cylinder has speed of 4 ms-1. The distance travelled by the cylinder on the inclined surface will be
(Take, g = 10 ms-2
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