A uniform rod of cross-sectional area 5 cm2 is subjected to a tensile force 100 N. PQ is a section which makes an angle of 45o with the axis of the rod. Then shear stress acting on that section is

Area of the section PQ, A'=AsinαForce acting along the section PQ=Fcosα∴Shear stress, τ=FcosαA/sinα=F2Asin2α=1002x5x10-4sin2x45oNm2                                                            ⇒τ=105 N/m2