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General Planar motion

Question

A uniform rod is falling without rotation on a smooth horizontal plane. Assuming the collision to be perfectly elastic, the angular velocity of the rod after striking the table is maximum when the rod makes an angle cos11 with the horizontal just before striking where  is not readable. Find .

Moderate
Solution

If v be the linear velocity of rod after impact (upwards), ωbe the angular velocity of rod and J be the linear impulse at A during impact, then by

Impulse - Momentum Theorem, we have

       J=Δp=pfpi J=mvmv0 J=mv+v0    .........(1)

 Further by  Angular  Impulse  Angular  Momentum  Theorem , we have 

J2cosθ==mℓ212ω    ........(2)

Since the collision is elastic, so at the point of impact e = 1.

 Relative speed  of approach = Relative speed  of separation 

 v0=v+2ωcosθ    .......(3)

Solving equations (1), (2) and (3), we get

ω=6v0cosθ1+3cos2θ

For ω to be maximum, we have

    =06v0dcosθ1+3cos2θ=01+3cos2θ(sinθ)cosθ(6sinθcosθ)1+3cos2θ2=01+3cos2θ=6cos2θ3cos2θ=1cosθ=13=3



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Two discs A & B having small projections, welded on their circumference , are free to rotate about their fixed axes, which are parallel to each other as shown in figure. The disc B starts rotating with angular velocity ω . It’s projection hits the projection of other disc at rest after time T. The coefficient of restitution is 12 . The two discs are of same radius but their moments of inertia are 4I and I respectively.


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