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A uniform rod of length b = 90 cm capable of turning about its end which is out of water, rests inclined to the vertical. If its specific gravity is 5/9,the length immersed in water (in cm) is_______

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answer is 30.

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Detailed Solution

Taking torque about hinge mgb2sin⁡θ=fBb−x2sin⁡θ(Ab)dmgb2=(Ax)dLgbx2;59b22=bx−x22 By solving it x=b3=903=30cm
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A uniform rod of length b = 90 cm capable of turning about its end which is out of water, rests inclined to the vertical. If its specific gravity is 5/9,the length immersed in water (in cm) is_______