A uniform rod of length L and density p is being pulled along a smooth floor with a horizontal acceleration α (see fig). The magnitude of the stress at thetransverse cross-section trough the mid-point of the rod is
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a
12ραL
b
ραL
c
ραL/2
d
ρα/2L
answer is A.
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Detailed Solution
Let A be the area of cross-section of the rod. The mass m of the rod will be L A pForce at the end of the rod =mα=LAραForce at the middle =12[LAρα]stress = Force per unit area =12LAραA=12ραL