A uniform rod of length l, mass m, cross-sectional area A and Young's modulus Y is rotated in horizontal plane about a fixed vertical axis passing through one end, with a constant angular velocity ω. Find the total extension in the rod due to the tension produced in the rod.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
mω2l23AY
b
mω3t33AY
c
mω2l34AY
d
mω3l23AY
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Y = T(x)A(∆e∆x); T(x) = ml(l-x)ω2(l-x2+x)⇒ T = mω22l(l2-x2) ; de = mω22AYl(l2-x2)dx⇒ mω22AYl(l3-l33) = mω2l23AYExtension = mω2l23AY