First slide

Angular momentum

Question

A uniform rod of length l is pivoted at point A. It is struck by a horizontal force which delivers an impulse J at a distance x from point A as shown in figure, impulse delivered by pivot is zero, if x is equal to :

Moderate

A

$\frac{2 l}{3}$
B

$\frac{l}{3}$
C

$\frac{3 l}{4}$
D

$\frac{l}{2}$

Solution

$\large J = mv\;\;\;\;J.x = I\omega = \frac{{m{l^2}}}{3}.\omega$
$\large v = \frac{l}{2}\omega \;\;\;x = \frac{2}{3}l$

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