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Q.

A uniform rod of length 2m and mass 5kg is lying on a horizontal surface. The work done in raising one end of the rod with the other end in contact with the surface until the rod makes an angle300 with the horizontal is, (g = 10ms-2) .

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a

25J

b

50J

c

25√3 J

d

50√3 J

answer is A.

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Detailed Solution

w = mgh = mg (l/2) sin θw = 5 x 10 x 1 x 1/2 = 25 J

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A uniform rod of length 2m and mass 5kg is lying on a horizontal surface. The work done in raising one end of the rod with the other end in contact with the surface until the rod makes an angle300 with the horizontal is, (g = 10ms-2) .