First slide

Applications of SHM

Question

A uniform rod of length 2.0 m is suspended through an end and is set into oscillation with small amplitude under gravity. The time period of oscillation is approximately

Moderate

A

1.60 sec
B

1.80 sec
C

2.0 sec
D

2.40 sec

Solution

This is the special case of physical pendulum and in this case $T = 2 π \sqrt{\frac{2 l}{3 g}}$
$\Rightarrow T = 2 \times 3 .14 \sqrt{\frac{2 \times 2}{3 \times 9 .8}} = 2 .31 \sec \approx 2 .4 \sec$

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