A uniform rod of length 2.0 m is suspended through an end and is set into oscillation with small amplitude under gravity. The time period of oscillation is approximately

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1.60 sec

1.80 sec

2.0 sec

2.40 sec

answer is D.

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Detailed Solution

This is the special case of physical pendulum and in this case T=2π2l3g ⇒T=2×3.142×23×9.8=2.31sec≈2.4sec

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