A uniform rod of length 2m. Velocity of point ‘B’ is 10 m/s as shown in figure and angular velocity of rod is 7 rad/s. Then

Let velocity at end A is v. The components of velocities at ends, along the length of the rod should be equal, 10cos⁡37∘=vcos⁡θ …….(i)And angular velocity ω=vsin⁡θ+6L ……(ii)From Eqs. (i) and (ii), we get v=82m/sNow from Eq. (i),cos⁡θ=10cos⁡37∘v=10×4/582=12⇒θ=45∘