Questions
A uniform rod of mass 15 kg and of length 5m is held stationary with the help of a light string as shown in the figure. The tension in the string is
detailed solution
Correct option is C
The free-body diagram of the rod is as shown in the figure. (Force exerted by the hinge on the rod are not shown.) Given : OBsinθ=3 ⇒sinθ=35 OA=OB2=52Now, take torque about the hinge,T×OBsinθ−15g×OAcosθ=0⇒T×3−15g×52×45=0⇒T=100NTalk to our academic expert!
Similar Questions
A 198 cm tall girl lies on a light (massless) board which is supported by two scales one under the top of her head and one beneath the bottom of her feet (Figure). The two scales read respectively 36 and 30 kg. What distance is the centre of gravity of this girl from the bottom of her feet?
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