A uniform rod of mass 3 kg and length 2m is lying on a horizontal surface. It is raised until it makes an angle 30∘ with vertical. The work done by gravity is (g=9.8ms-2)
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a
14.7 J
b
-14.7 J
c
8.49J
d
-8.49J
answer is B.
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Detailed Solution
h=l2cos30∘h=22×32=32mW=F→.S→=mg h cos 180W=3×9.8×32×(−1)W=−14.7J