Q.

A uniform rod of mass m = 5 kg and length L = 90cm rests on a smooth horizontal surface. One of the ends of the rod is struck with the impulse J = 3 N.s in a horizontal direction perpendicular to the rod. As a result, the rod attains the momentum p = 3 N.s . Find the force (in newtons) with which one half of the rod will apply on the other half in the process of motion.

Difficult

Unlock the Full Solution and Master the Concept

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya

answer is 9.

(Detailed Solution Below)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Angular impulse = change in angular momentum (about point C)3 ℓ2=(m ℓ212)ω  ⇒ ω=3 x 6mℓ =185×0.9=4 rad/sBy Newton's 2 nd Law       T=(m2)(ω2)(ℓ4) ⇒T       = mω2ℓ8=5×16×0.98=9N
ctaimg
Choose your Grade and Exam
edit icon

Connect with our

Expert Counsellors

access to India's best teachers with a record of producing top rankers year on year.

+91

We will send a verification code via OTP.

whats app icon