, A uniform rod of mass m and length / is held inclined at an angle of 600 with the vertical. What will-be potential energy of the rod in this position ?

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m g I

m g I/2

m g I/3

m g I /4

answer is D.

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Detailed Solution

See fig. (12). Let the center of gravity of the rod be at aheight ft. From figure,h=OCsin⁡30∘=(l/2)sin⁡30∘=l/4 P.E. =mgh=mgl/4

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