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Q.

A uniform rod of mass M and length L is hinged at lower end on a fixed horizontal table. The rod can rotate freely in vertical plane and there is no friction at the hinge. A ball of mass M and radius R=L3 is placed in contact with the vertical rod and a horizontal force F is applied at the upper end of the rod. There is no friction between rod and the ball and there is sufficient friction between ball and ground for pure rolling. Mark the correct statement(s). (assume the  ball to be a uniform solid sphere)

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a

The acceleration of centre of mass of ball just after the application of force is 1522  FM

b

The angular acceleration of rod just after the application of force is 4522  FML

c

The horizontal component of hinge reaction on the rod just after application of force is  4344 F

d

The horizontal component of hinge reaction on the rod just after application of force is  4443  F

answer is A.

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Detailed Solution

For ball: N⋅R=25+1MR2a0R⇒N=75Ma0      .....(i)     For rod : F−N3l=Ml23α   .....(ii)  Also, lα3=a0  (iii) From (i), (ii) & (iii) a0=1522  FM  ;  α=3a0l=45 F22  Mlb) Horizontal hinge reaction  Rx is horizontal Hinge reaction and Ry is vertical Hinge reactionF+Rx-N=MacomRx=-F+N+Macom= -F+75Ma0+Mαl2=-F+75M15F22M+M45F22Mll2 =43F44
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