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Q.

A uniform rod of mass M and length L is kept on a horizontal surface. The rod receives an impulse J at its lowest point, normal to its length as shown, then choose the correct statement.

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a

The velocity of point P just after impact is 2JM

b

The velocity of point P just after impact is JM

c

Kinetic energy after impact is J2M

d

Kinetic energy after impact is 2J2M

answer is D.

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Detailed Solution

Velocity of the centre of the rod Vc=JM Angular velocity ω=JL/2ML212=6JML So VP=JM-ωL/6=0 Kinetic energy = 12MJM2+12112ML26JML2=2J2M
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