A uniform rod of mass M and length L is kept on a horizontal surface. The rod receives an impulse J at its lowest point, normal to its length as shown, then choose the correct statement.
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a
The velocity of point P just after impact is 2JM
b
The velocity of point P just after impact is JM
c
Kinetic energy after impact is J2M
d
Kinetic energy after impact is 2J2M
answer is D.
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Detailed Solution
Velocity of the centre of the rod Vc=JM Angular velocity ω=JL/2ML212=6JML So VP=JM-ωL/6=0 Kinetic energy = 12MJM2+12112ML26JML2=2J2M