A uniform rod OB of length 1 m, cross-sectional area 0.012 m2 and relative density 2.0 is free to rotate about O in vertical plane. The rod is held with a horizontal string AB which can withstand a maximum tension of 45 N. The rod and string system is kept in water as shown in figure. The maximum value of angle α which the rod can make with vertical without breaking the string is
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a
450
b
370
c
530
d
600
answer is B.
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Detailed Solution
F.B. of rod:W=(0.012)(1)2×103(10)=240NFb=(0.012)(1)103(10)=120NTorque about O:(For equilibrium)(240−120)sinα2=45(cosα)⇒ tanα=90120=34⇒α=37∘