A uniform rood AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is ml23 , the initial angular acceleration of the rod will be

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2g3l

mgl2

3gl2

3g2l

answer is D.

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Detailed Solution

I=ml23 T=Iα=mgl2ml23α=mgl2 α=3g2l

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