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A uniform rope of length I lies on a table. If the coefficient of friction is μ, then the maximum length l1 of the hanging part of the rope which can overhang from the edge of the table without sliding down is

a
l/ μ
b
l/(μ +1)
c
μl/(μ +1)
d
μl/(μ -1)

detailed solution

Correct option is C

In critical case, weight of hanging part = force of friction of the part of rope lying on table.∴  ml·l1g=μmll-l1gSolving above equation, we getl1=μ1+μl

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