A uniform rope of length L and mass m1 hangs vertically from a rigid support. A block of mass m2is attached to the free end of the rope. A transverse pulse of wavelength λ1 is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is λ2. The ratio λ2λ1 is

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m2m1

m1+m2m1

m1m2

m1+m2m2

answer is D.

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Detailed Solution

Wavelength of pulse at the lower end λ1∝ velocity v1=T1μ Similarly, λ2∝v2=T2μ∴λ2λ1=T2T1=m1+m2gm2g=m1+m2m2

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