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A uniform solid disc is rolling on a horizontal surface. At a certain instant B is the point of contact and A is at height 2R from ground, where R is radius of disc:

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By Expert Faculty of Sri Chaitanya
a
The magnitude of the angular momentum of the disc about B is thrice that about A.
b
The angular momentum of the disc about A is anticlockwise.
c
The angular momentum of the disc about B is clockwise
d
The angular momentum of the disc about A is equal to that about B.
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detailed solution

Correct option is A

L→=r→×MV→cm+IcmωLB=mvR+12mR2ω                (v=rω)LB=32mvRLA=−mvR+12mR2ω⇒12mvR∴ LB=3LA′As  LA=−ve          i.e., in (ACW) direction        LB=+ ve         i.e., in (CW) direction


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In the figure shown mass of both, the spherical body and block is m. Moment of inertia of the spherical body about centre of mass is 2mR2. The spherical body rolls on the horizontal surface. There is no slipping at any surfaces in contact. The ratio of kinetic energy of the spherical body to that of block is

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