A uniform solid disc is rolling on a horizontal surface. At a certain instant B is the point of contact and A is at height 2R from ground, where R is radius of disc:

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The magnitude of the angular momentum of the disc about B is thrice that about A.

The angular momentum of the disc about A is anticlockwise.

The angular momentum of the disc about B is clockwise

The angular momentum of the disc about A is equal to that about B.

answer is A.

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Detailed Solution

L→=r→×MV→cm+IcmωLB=mvR+12mR2ω (v=rω)LB=32mvRLA=−mvR+12mR2ω⇒12mvR∴ LB=3LA′As LA=−ve i.e., in (ACW) direction LB=+ ve i.e., in (CW) direction

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