Questions
A uniform solid disc is rolling on a horizontal surface. At a certain instant B is the point of contact and A is at height 2R from ground, where R is radius of disc:
detailed solution
Correct option is A
L→=r→×MV→cm+IcmωLB=mvR+12mR2ω (v=rω)LB=32mvRLA=−mvR+12mR2ω⇒12mvR∴ LB=3LA′As LA=−ve i.e., in (ACW) direction LB=+ ve i.e., in (CW) directionTalk to our academic expert!
Similar Questions
In the figure shown mass of both, the spherical body and block is m. Moment of inertia of the spherical body about centre of mass is 2mR2. The spherical body rolls on the horizontal surface. There is no slipping at any surfaces in contact. The ratio of kinetic energy of the spherical body to that of block is
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