A uniform solid sphere of mass m is lying at rest between a vertical wall and a fixed inclined plane as shown. There is no friction between sphere and the vertical wall but coefficient of friction between the sphere and the fixed inclined plane is μ=1/2. Then the magnitude of frictional force exerted by fixed inclined plane on sphere is -(g is acceleration due to gravity)
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a
mg2
b
34mg
c
mg
d
0
answer is D.
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Detailed Solution
All forces on sphere pass through its center except the force of friction exerted by inclined plane. Since net torque on sphere in equilibrium about its center is zero, the torque on sphere due to frictional force about its center must be zero. Hence frictional force on cylinder is zero.