First slide

Applications of SHM

Question

A uniform spring of force constant k is cut into two pieces, the lengths of which are in the ratio 1 : 2. The ratio of the force constants of the shorter and the longer pieces is

Easy

A

1 : 3
B

1 : 2
C

2 : 3
D

2 : 1

Solution

Force constant $(k) \propto \frac{1}{Length of the string (l)}$
$\Rightarrow \frac{k_{1}}{k_{2}} = \frac{l_{2}}{l_{1}} = \frac{2}{1}$

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