First slide

Stress and strain

Question

A uniform steel bar of cross-sectional area A and length L is suspended, so that it hangs vertically. The stress at the middle point of the bar is ( $ρ$ is the density of steel)

Moderate

A

$\frac{L}{2 A} ρ g$
B

$\frac{L ρ g}{2}$
C

$\frac{L A}{ρ g}$
D

$L ρ g$

Solution

At middle, T = weight of half the length of steel bar
$= (\frac{L}{2}) Apg$
$∴ Stress = \frac{T}{A} = \frac{L ρ g}{2}$

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