A uniform steel bar of cross-sectional area A and length L is suspended, so that it hangs vertically. The stress at the middle point of the bar is (ρ is the density of steel)
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a
L2Aρg
b
Lρg2
c
LAρg
d
Lρg
answer is B.
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Detailed Solution
At middle, T = weight of half the length of steel bar=L2Apg∴ Stress =TA=Lρg2