A uniform stick of mass M and length L is pivoted at its centre. Its ends are tied to two springs each of force constant K. In the position shown in figure, the strings are in their natural length. When the string is displaced through a small angle θ and released. The stick:
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a
executes non-periodic motion
b
executes periodic motion which is not simple harmonic
c
executes S.H.M. of frequency 12π6KM
d
executes S.H.M. of frequency 12πK2M
answer is C.
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Detailed Solution
If stick is rotated through a small angle θ, the spring is stretched by a distance L2θ. Therefore restoring force is spring = K(L2θ). Each spring causes a torque τ(= Fd) =(KLθ2)L2 in the same direction. Therefore equation of rotational motion isτ = Iα-2(KLθ2)L2 = Iα with I = ML212α = -(6KM)θStandard equation of angular S.H.M. is α = -ω2θω2 = 6KMfrequency f = ω2π =12π6KM