A uniform thin bar of mass 6 kg and length 2.4 meter is bent to make an equilateral hexagon. The moment of inertia about an axis passing through the centre of mass and perpendicular to the plane of hexagon is ……… ×10−1 kg m2
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answer is 8.
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Detailed Solution
Mass of each side =m6 Dlstance PO=32a Here, m=6kg,a=2.46=0.4mMOI of one side about O=m6a212+(PO)2 MOl of all sides =I=6×m6a212+3a24=5ma26 where a=0.4⇒I=56×6×(0.4)2=0.8=8×10−1kg−m2