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Q.

A uniform thin bar of mass 6 m and length 12L is bent to make a regular hexagon. Its moment of inertia about an axis passing through the centre of mass and perpendicular to the plane of the hexagon is:

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a

20 mL2

b

6 mL2

c

125 mL2

d

30 mL2

answer is A.

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Detailed Solution

x = 2L cos 30° = L3I = 6(m(2L)212+mx2) = 20mL2
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