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Questions  

A uniform thin rod of length l and mass m is hinged at a distance l/4 from one of the end and released from horizontal position as shown in the figure. The angular
velocity of the rod as it passes the vertical position is 

a
25g7l
b
26g7l
c
3g7l
d
2gl

detailed solution

Correct option is B

Loss in potential energy = Gain in Kinetic energy⇒mgl4=12ml212+ml42ω2⇒ω=24g7l=26g7l

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Similar Questions

The condition of equilibrium is satisfied when resultant of all forces acting on body vanishes and also no net torque acts on the body. However body can be different types of equilibrium as stable, unstable, neutral or may be having pure rotation when no resultant force acts on the body. Different conditions of equilibrium or rotational motion can be known by different types of energy it possesses. Column I mentions the state of body and column II mentions the type of energy it possesses. Match the correct options in two columns

COLUMN_I                                                             COLUMN_II

A)  Body in stable equilibrium                P) Rotational kinetic energy

 B)  Body in unstable equilibrium           Q) Minimum potential   

                                                                 energy

C)   Body in neutral equilibrium         R)Maximum potential energy

D) Body in pure rotational motion     S) Constant potential energy


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