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Q.

A uniform wire of cross-sectional area A and Young's modulus Y is stretched within the elastic limit. If S is the stress in the wire, the elastic energy density stored in the wire in terms of the given parameters is

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a

S2Y

b

2YS2

c

S22Y

d

S2Y

answer is C.

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Detailed Solution

Let the strain be ε. Then Y=Sε or ε=SY. Now energy density =12 stress × strain =12×S×SY=S22Y. Hence the correct choice is (3).
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