First slide

Ohm's law

Question

A uniform wire of resistance 9 Q is cut into 3 equal parts. They are connected in the form of equilateral triangle ABC. A cell of e.m.f. 2 V and negligible internal resistance is connected across B and C. Potential difference across AB is

Moderate

A

1 V
B

2 V
C

3 V
D

0.5 V

Solution

The circuit can be drawn as follows:
Equivalent resistance, $R = \frac{3 \times (3 + 3)}{3 + (3 + 3)} = 2 Ω$
Current, $i = \frac{2}{2} = 1 A . So, i_{1} = 1 \times (\frac{3}{3 + 6}) = \frac{1}{3} A .$
Potential difference between A and B $= \frac{1}{3} \times 3 = 1 V .$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App