A uniform wooden stick of mass 1.6 kg and length l rests in an inclined manner on a smooth, vertical wall of height h

Vertical direction, N+R2=mg=1.6×10⇒N=16−R2Horizontal Direction, f=3R2⇒R=2f3 About A,TCW=TACW⇒(R)hcos⁡30=(mg)l2cos⁡60⇒R2h3=(16)l2×12⇒hl=23RIf the reaction of the floor on stick is taken as normal reaction, then N=R  ⇒16−R2=R ⇒R=323Nf = 32R=32323=1633Nhl=23R=2332/3=3316