First slide
Gauss's Law
Question

A uniformly charged and infinitely long line having a liner charge density )., is placed at a normal distance y from a point 0. Consider a sphere of radius R with O as centre and R > y. Electric flux through the surface of the sphere is

Difficult
Solution

 Electric flux, SE.ds=qin ε0

qin is the charge enclosed by the Gaussian surface which, in the present case, is the surface of given sphere. As shown, length AB of line lies inside the sphere.

 In ΔOO'A R2=y2+O'A2   O'A=R2-y2  and   AB=2R2-y2  Charge on length AB=2R2-y2×λ    Electric flux =SE¯.ds=2λR2-y2ε0

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