A uniformly charged ring of charge Q and radius R is folded across its diameter such that two halves make an angle 60° with each other then net electric field at centre 'O' of ring is equal to :

• A

  $\frac{\sqrt{3}\mathrm{kQ}}{{\mathrm{\pi R}}^2}$

• B

  $\frac{2\sqrt{3}\mathrm{kQ}}{{\mathrm{\pi R}}^2}$

• C

  $\frac{2\mathrm{kQ}}{{\mathrm{\pi R}}^2}$

• D

  $\frac{4\mathrm{kQ}}{{\mathrm{\pi R}}^2}$