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A uniformly thick wheel with moment of inertia I and radius R is free to rotate about its centre of mass (see fig) . A massless string is wrapped over its rim and two blocks of masses  m1andm2m1>m2 are attached to the ends of the string. The system is released from rest. The angular speed of the wheel when m1 descents by a distance h is

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a
2m1+m2ghm1+m2R2+I12
b
m1−m2m1+m2R2+I12gh
c
m1+m2m1+m2R2+I12gh
d
2m1−m2ghm1+m2R2+I12

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detailed solution

Correct option is D

According to work energy theoremWTotal=ΔKEm1gh−m2gh=12m1+m2v2+12Iω2          ​⇒m1−m2gh=12m1+m2R2ω2+12Iω2      ∵v=Rω​⇒m1−m2gh=ω2m1+m2R2+I2         ​⇒ω=2m1−m2ghm1+m2R2+I1/2


Similar Questions

The condition of equilibrium is satisfied when resultant of all forces acting on body vanishes and also no net torque acts on the body. However body can be different types of equilibrium as stable, unstable, neutral or may be having pure rotation when no resultant force acts on the body. Different conditions of equilibrium or rotational motion can be known by different types of energy it possesses. Column I mentions the state of body and column II mentions the type of energy it possesses. Match the correct options in two columns

COLUMN_I                                                             COLUMN_II

A)  Body in stable equilibrium                P) Rotational kinetic energy

 B)  Body in unstable equilibrium           Q) Minimum potential   

                                                                 energy

C)   Body in neutral equilibrium         R)Maximum potential energy

D) Body in pure rotational motion     S) Constant potential energy


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