A uniformly thick wheel with moment of inertia I and radius R is free to rotate about its centre of mass (see fig) . A massless string is wrapped over its rim and two blocks of masses m1 and m2m1>m2 are attached to the ends of the string. The system is released from rest. The angular speed of the wheel when m1 descents by a distance h is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
2m1+m2ghm1+m2R2+I12
b
m1−m2m1+m2R2+I12gh
c
m1+m2m1+m2R2+I12gh
d
2m1−m2ghm1+m2R2+I12
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
According to work energy theoremWTotal=ΔKEm1gh−m2gh=12m1+m2v2+12Iω2 ⇒m1−m2gh=12m1+m2R2ω2+12Iω2 ∵v=Rω⇒m1−m2gh=ω2m1+m2R2+I2 ⇒ω=2m1−m2ghm1+m2R2+I1/2