A uniformly thick wheel with moment of inertia I and radius R is free to rotate about its centre of mass (see fig) . A massless string is wrapped over its rim and two blocks of masses m1 and m2m1>m2 are attached to the ends of the string. The system is released from rest. The angular speed of the wheel when m1 descents by a distance h is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

2m1+m2ghm1+m2R2+I12

m1−m2m1+m2R2+I12gh

m1+m2m1+m2R2+I12gh

2m1−m2ghm1+m2R2+I12

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

According to work energy theoremWTotal=ΔKEm1gh−m2gh=12m1+m2v2+12Iω2 ⇒m1−m2gh=12m1+m2R2ω2+12Iω2 ∵v=Rω⇒m1−m2gh=ω2m1+m2R2+I2 ⇒ω=2m1−m2ghm1+m2R2+I1/2

Watch 3-min video & get full concept clarity