First slide

Force on a current carrying wire placed in a magnetic field

Question

The unit of electric current "ampere" is the current which when flowing through each of two parallel wires spaced 1 m apart in vacuum and of infinite length will give rise to a force between them equal to

Easy

A

1 N/m
B

$2 \times 10^{- 7} N / m$
C

$1 \times 10^{- 2} N / m$
D

$4 π \times 10^{- 7} N / m$

Solution

Force per unit length on two parallel current carrying conductors is given by $\frac{F}{l} = 10^{- 7} \times 2 \frac{i_{1} i_{2}}{a}$
$\Rightarrow \frac{F}{l} = 10^{- 7} \times 2 \times \frac{1 \times 1}{1} = 2 \times 10^{- 7} N / m$

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