Unit mass of a liquid with volume V1 is completely changed into a gas of volume V2 at a constant external pressure ρ at temperature T. If the latent heat of evaporation is L, then the increase in the internal energy of the system is
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a
zero
b
pV2−V1
c
L−pV2−V1
d
L
answer is C.
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Detailed Solution
First law of thermodynamics given, ΔQ=ΔU+pΔV⇒ mL=ΔU+pV2−V1⇒ ΔU=L−pV2−V1 (∵m=1)
Unit mass of a liquid with volume V1 is completely changed into a gas of volume V2 at a constant external pressure ρ at temperature T. If the latent heat of evaporation is L, then the increase in the internal energy of the system is