Units

Question

The unit of permittivity of free space, ${\epsilon}_{0}$, is

Easy

Solution

Force between two charges

$F=\frac{1}{4\pi {\epsilon}_{0}}\frac{{q}^{2}}{{r}^{2}}\Rightarrow {\epsilon}_{0}=\frac{1}{4\pi}\frac{{q}^{2}}{F{r}^{2}}={C}^{2}/N-{m}^{2}$

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