First slide

Radiation

Question

The unit of thermal conductivity is

Easy

A

${Wm}^{- 1} K^{- 1}$
B

${JmK}^{- 1}$
C

$J m^{- 1} K^{- 1}$
D

$W m K^{- 1}$

Solution

$\frac{dQ}{dt} = - (K) A \frac{dT}{dx}$
$\frac{J}{s} = (K) m^{- 2} \frac{Kelvin}{m} \Rightarrow W = (K) m^{2} \frac{K}{m}$
Hence unit of thermal conductivity = ${Wm}^{- 1} K^{- 1}$

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