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Questions  

The unit of thermal conductivity is

a
Wm-1K-1
b
JmK-1
c
J m-1K-1
d
W m K-1

detailed solution

Correct option is A

dQdt = -(K)AdTdxJs = (K)m-2Kelvinm   ⇒ W = (K)m2KmHence unit of thermal conductivity = Wm-1K-1

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