First slide

Conduction

Question

The unit of thermal conductivity is

Easy

A

${Wm}^{- 1} K^{- 1}$
B

${JmK}^{- 1}$
C

${Jm}^{- 1} K^{- 1}$
D

${WmK}^{- 1}$

Solution

$K = \frac{Qx}{A (T_{1} - T_{2}) t}$ where Q is the amount of heat flow, x is the thickness of the slab, A is the area of cross-section, and t is the time taken.
$K = \frac{Jm}{m^{2} K s} = W \frac{1}{m} \frac{1}{K} = {Wm}^{- 1} K^{- 1}$

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